Need More Algebra 1 help PLEASE PLEASE?
The perpendicular sides of a trianglular rug measure 6 feet and 9 feet. Calculate the area of the rug.
(a) 39 sq ft
(b) 27 sq ft
(c) 21 sq ft
(d) 19 sq ft
[[[[Bonus]]]] answer if you want, thank you so much 
Find the break-even point for the given cost and revenue equations. Round to the nearest whole unit
C = 15n + 269,000
R = 95n
(a) 80
(b) 2445
(c) 3363
(d) 110
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July 8th, 2010 at 4:38 am
For the first question, the area of a triangle is
A = 1/2(Base)(Height)
A = 1/2(6)(9)
A = 1/2(54)
A = 27 sq ft
The answer is (b)
For the second question you are looking for when the equations are equal to each other
15n + 269,000 = 95n
269,000 = 95n - 15n
269,000 = 80n
(269,000/80) = 80n/80
3362.5 = n
Therefore your answer is (c) 3363
July 8th, 2010 at 4:38 am
B to the first one
July 8th, 2010 at 4:38 am
The answer is B) 27 square feet
July 8th, 2010 at 4:38 am
1) how do you find the area of a square? a rectangle? if you cut a rectangle from corner to corner, what shape do You get? what is the area of each piece?
THINK
bonus Break even is when total cost and total revenue add to zero
label the numbers, 15 is $, N is just units or plain number
C + R = 0 solve for n using algebra.
it is time to learn not just ask for answers
July 8th, 2010 at 4:38 am
Area = 1/2 * base * height
= 1/2 * 6 * 9
= 27 sq ft >>>>>>>>>>. B
C = 15n + 269,000
R = 95n
R = C
15n + 269000 = 95 n
269000 = 80n
n = 269000/80 = 33 625