I know this should be simple! It's frustrating!?
A rectangular Persian carpet has a perimeter of 160 inches. The length of the carpet is 18 in. more than the width. What are the dimensions of the carpet?
A rectangular Persian carpet has a perimeter of 160 inches. The length of the carpet is 18 in. more than the width. What are the dimensions of the carpet?
March 2nd, 2010 at 7:30 pm
let x = length = 18 + y
y = width = unknown
Perimeter = 2length + 2 width = 2x + 2y = 160
–> 2y = 160 - 2x
–> 2y = 160 - 2(18 + y)
–> 2y = 160 - 36 - 2y
–> 4y = 124
–> y = 31 is the width
x = 18 + y
x = 18 + 31
x = 49 is the length
to check:
perimeter = 160 = 49(2) + 31(2)
= 98 + 62
= 160
There you go. I hope its clear…
March 2nd, 2010 at 7:30 pm
length is 18 more than the width; l = w + 18
perimeter (2l + 2w) = 160
2l + 2w = 160
substitute w + 18 in for l
2(w + 18) + 2w = 160
2w + 26 + 2w = 160
4w = 134
w = 33.5
l = w + 18 = 33.5 + 18 = 51.5
your dimensions are 33.5 x 51.5
hope that helps!
March 2nd, 2010 at 7:30 pm
x + x + (x + 18) + (x + 18) = 160
4x +36 = 160
4x = 124
x = 31
dimensions are 31 in. x 49 in.
March 2nd, 2010 at 7:30 pm
It’s not possible
March 2nd, 2010 at 7:30 pm
width = x
length = (x + 18)
perimeter = 2w + 2l = 2x + 2(x + 18) = 160
2x + 2x + 36 = 160
4x = 124
x = 31
width = 31
length = 31 + 18 = 49
2w + 2l = 160 checks
March 2nd, 2010 at 7:30 pm
160 - (18 * 2) = 124
124/4 = 31
31+18 = 49
49 x 31 = 1519
March 2nd, 2010 at 7:30 pm
Length= 49
Width= 31
March 2nd, 2010 at 7:30 pm
P = 2L + 2W 160
Length = W + 18
2(W + 18) + 2W = 160
2W + 36 + 2W = 160
4W = 160 - 36
W = 124 / 4
……………………W = 31 in.
L = 31 +18
…………………..L = 49 in.
Check
2W + 2L = 160
62 + 98 = 160
Sure couldn’t ride on a flying carpet that small.
Darn Persians…they don’t know math.